Talk:Ainz Ooal Gown/Abilities and Powers/@comment-37782702-20190116012237/@comment-37.16.124.17-20191017100257

Wish Upon A Star in the New World acts as a spell that can achieve anything, assuming one provides it with enough experience. Each wish has a value that you need to fulfill or otherwise, the wish won't happen while the experience is spent. If too much experience is also given, you would lose all of the experience invested even if you could achieve the wish with less experience. Based on this, there should be some method to scale the size of the wish according to objective standards similarly to how Exchange Box converts items into YGGDRASIL gold based on their objective value. This is to avoid situations where someone's wish might cost a lot less than someone else's when wishing for the same thing, just because they don't want it as much.

Now to estimate the value of all World-Class Items. Because World-Class Items are balance breakers and with a single one you could overthrow most opponents, World-Class Items should have the highest value of any item. Objectively, it's a high-class item with immense power. I'd say that just to obtain a single one, you should be wasting levels upon levels.

Now could Ainz use Shooting Start to wish for all WCI's without any XP cost? I'd also say no to this. Shooting Star only gave the caster a few spells from the beginning. One could spend more experience to obtain more choices if the wish didn't suit you in YGGDRASIL. However, in the New World choices are no longer a thing as Ainz stated you could wish for anything. The ring itself is never stated to grant all wishes free of charge, but only gave 10 options which is equal to 1 level worth of experience. Using one level worth of experience only, I highly doubt you could summon a single World-Class Item, let alone them all.

Of course, this is purely how I view the change in nature in the spell. Wish Upon A Star has changed too much after the transition to the New World, and without a clear statement from the author, there won't be an explanation to this question.